Leap Year Finder in Python
# a year is leap year if it is evenly divisble by 4 # a year is leap year if it is evenly divisible by 4 but may not by 100 # a year is leap year if it is evenly divisible by 4, by 100 as well as by 400 print("Welcome to Leap Year Finder!") while True: year = int(input("Plz enter the year: ")) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print(f"{year} is a Leap Year.") else: print(f"{year} is not a Leap Year.") else: print(f"{year} is a Leap Year.") else: print(f"{year} is not a Leap Year.")